i = square root of minus one
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Depends on the circuit. If you want the admittance (inverse of the impedance) of the component, say so.
But what is 1.5 – 2i ? It could be the admittance, the impedance, the voltage, the current? which is is?
And you say "components", plural. how many are there and how are they connected? Please try to list complete and solvable problems.
on the off chance that that is the impedance, then just invert it to get admittance.
1 / (1.5 – 2i) is the admittance
to rationalize it, multiply by the complex conjugate over itself
Y = 1 / (1.5 – 2i)
Y = [ 1 / (1.5 – 2i) ] [ (1.5 + 2i) / (1.5 + 2i) ]
Y = (1.5 + 2i) / (1.5² + 4)
Y = (1.5 + 2i) / (6.25)
Y = 0.24 + 0.32i
But what is 1.5 – 2i ? It could be the admittance, the impedance, the voltage, the current? which is is?
And you say "components", plural. how many are there and how are they connected? Please try to list complete and solvable problems.
on the off chance that that is the impedance, then just invert it to get admittance.
1 / (1.5 – 2i) is the admittance
to rationalize it, multiply by the complex conjugate over itself
Y = 1 / (1.5 – 2i)
Y = [ 1 / (1.5 – 2i) ] [ (1.5 + 2i) / (1.5 + 2i) ]
Y = (1.5 + 2i) / (1.5² + 4)
Y = (1.5 + 2i) / (6.25)
Y = 0.24 + 0.32i