The problem asks to find the force in each member using method of joints and whether or not each member is in tension of compression.
http://desmond.imageshack.us/Himg856/sca…
I missed about 4 lectures of this chapter due to a family emergency that I caused me to be home from school for a few days. I'm having trouble with trusses in general. I've read the sections in the book and asked classmates for help but I still don't understand. I don't have time to talk to my professor or get tutoring because I have a quiz tomorrow on this stuff. If someone could help guide me through this, that would be great
http://desmond.imageshack.us/Himg856/sca…
I missed about 4 lectures of this chapter due to a family emergency that I caused me to be home from school for a few days. I'm having trouble with trusses in general. I've read the sections in the book and asked classmates for help but I still don't understand. I don't have time to talk to my professor or get tutoring because I have a quiz tomorrow on this stuff. If someone could help guide me through this, that would be great
-
You know I can't do the solution for you as it is really long and hard. But I will just leave pointers on how to solve this (in order of usage, of course). Better if you will just use Method of Joints (instead of Method of Sections), because this is easier.
1) Points A, B, C, D E, F, G are all "joints" in the trusses.
2) Support G acts as a roller, with a single reaction force acting AWAY the from the truss (or arrow towards the LEFT) .
3) Support A acts as a hinge, and being a hinge it has 2 reaction forces. The first reaction force is upwards (to support ALL the downward forces) and the second force is acting TOWARDS the truss (or arrow towards the RIGHT).
4) Using your FBD, and by summation of all vertical forces, the upward reaction force in A (Rav).
Rav = (24 kips + 24 kips + 24 kips) = 72 kips.
5) Summing moments @ point A (clockwise rotation is positive), the reaction force at G (Rg).
Rg = [(24*30) + (24*20) + (24*10)] / 15 = 96 kips.
6) Summing moments @ point G (clockwise rotation is positive), the horizontal reaction force at A (Rah).
Rah = [(24*30) + (24*20) + (24*10)] / 15 = 96 kips.
7) Determine all the angles in the truss.
8) In ALL trusses, ALL members at the foot of the truss (members AB, BC, and CD) are compressive forces. ALL other members are tensile forces.
1) Points A, B, C, D E, F, G are all "joints" in the trusses.
2) Support G acts as a roller, with a single reaction force acting AWAY the from the truss (or arrow towards the LEFT) .
3) Support A acts as a hinge, and being a hinge it has 2 reaction forces. The first reaction force is upwards (to support ALL the downward forces) and the second force is acting TOWARDS the truss (or arrow towards the RIGHT).
4) Using your FBD, and by summation of all vertical forces, the upward reaction force in A (Rav).
Rav = (24 kips + 24 kips + 24 kips) = 72 kips.
5) Summing moments @ point A (clockwise rotation is positive), the reaction force at G (Rg).
Rg = [(24*30) + (24*20) + (24*10)] / 15 = 96 kips.
6) Summing moments @ point G (clockwise rotation is positive), the horizontal reaction force at A (Rah).
Rah = [(24*30) + (24*20) + (24*10)] / 15 = 96 kips.
7) Determine all the angles in the truss.
8) In ALL trusses, ALL members at the foot of the truss (members AB, BC, and CD) are compressive forces. ALL other members are tensile forces.
12
keywords: would,this,problem,truss,about,How,solving,go,statics,How would I go about solving this statics truss problem