Three phase system electrical engineering question help please

Line voltage is 415v there fore Red phase voltage is 240v now i want red phasor current , and Z=4<35 degrees ohm's so using i=Voltage phasor/Z
i have red phasor current 60<-35degrees Amps

i understand this but other two phase's values given as yellow is 60<-155 degrees
blue is given 60<85 degrees

i know how it is for 60 for all of them but how do i get the angle i do know the red phasor angle because its reference and therfore 0 degrees then -35 from that is -35 but other two how do i get them

thanks

The phases voltages are 120 degrees apart (in an ideal world).

Vred = 240<0
Vyel = 240<-120
Vblu = 240<120

I = V/Z
Ired = 240<0 / 4<35 = (240/4)<(0-35) = 60<-35
Iyel = 240<-120 / 4<35 = (240/4)<(-120-35) = 60<-155
Iblu = 240<120 / 4<35 = (240/4)<(120-35) = 60<85

Remember to subtract the angle in the denominator from the angle in the numerator.