Can someone please help me with this trig problem? Thank you SO much
Favorites|Homepage
Subscriptions | sitemap
HOME > > Can someone please help me with this trig problem? Thank you SO much

Can someone please help me with this trig problem? Thank you SO much

[From: ] [author: ] [Date: 11-12-29] [Hit: ]
Anyway, #1 is the best answer, although #4 is also correct.#2 and #3 are incorrect.sin kπ = 0 for any integer k.This includes sin 0,......
It's number 23
http://imageshack.us/f/855/screenshot201…

-
I looked at #23. It appears there's a typo. The question asks you to find "q", but in all the answers they use "k". I think they meant "k" rather than "q" in the question.

Anyway, #1 is the best answer, although #4 is also correct. #2 and #3 are incorrect. Here's why:

sin kπ = 0 for any integer k. This includes sin 0, sin π, sin 2π, sin 3π, and so on (and sin -π too). Answer 1 fits this model.

Answer 4 is the same, but only for even multiples of π. So #4 is correct, but it's not as good as #1.

The other two answers, however, are incorrect. By adding π/2 (which is 90°), you're setting up 90° angles, and the sine of 90° (which is the sine of π/2) is one, not zero.

You wanted an explanation, so I hope this makes some sense to you.

-
answer 1/
1
keywords: with,Thank,Can,someone,trig,problem,please,me,SO,much,you,help,this,Can someone please help me with this trig problem? Thank you SO much
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .