Gas Laws Question!!!!!

Oxygen gas, generated by the reaction 2KClO3(s)-> 2KCl(s)+3O2(g) is collected over water at 27 degrees Celsius in a 2.00L vessel at a total pressure of 760torr. (The vapor pressure of H2O at 27 degress Cesius is 26.0 torr) How many moles of KClO3 were consumed in the reaction?

Answer is 0.0527 moles

Plz help xP i have to study for my finals D:

PV = nRT
n = PV / RT = (760 torr - 26.0 torr) x (2.00 L) /
((62.36367 L Torr/K mol) x (27 + 273 K)) = 0.078464 mol O2

2 KClO3 → 2 KCl + 3 O2

(0.078464 mol O2) x (2 mol KClO3 / 3 mol O2) = 0.0523 mol KClO3