A circular curve of highway is designed for traffic moving at 50 km/h.
(a) If the radius of the curve is 150 m, what is the correct angle of banking of the road?
answer: 7.476 degrees
(b) If the curve were not banked, what would be the minimum coefficient of friction between tires and road that would keep traffic from skidding out of the turn when traveling at 50 km/h?
μs =
I understand banked curves a little, and I got that the answer to part a was 7.476 degrees (it's right). could someone show me how part b works, with a detailed explanation? greatly appreciated, thanks!
(a) If the radius of the curve is 150 m, what is the correct angle of banking of the road?
answer: 7.476 degrees
(b) If the curve were not banked, what would be the minimum coefficient of friction between tires and road that would keep traffic from skidding out of the turn when traveling at 50 km/h?
μs =
I understand banked curves a little, and I got that the answer to part a was 7.476 degrees (it's right). could someone show me how part b works, with a detailed explanation? greatly appreciated, thanks!
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(50/3.6) = 13.89m/sec.
Force = (v^2/r) = 1.2862N.
a) Arctan (f/g)) = arctan (1.2862/9.8) = 7.477 degrees.
b) The force is the same, so coefficient minimum = (f/g) = 1.2862/9.8, = 0.13.
Remember a coefficient is a ratio. It will hold true regardless of mass.
Force = mv^2/r, but when mass is not given, assume 1kg., = 9.8N.
Force = (v^2/r) = 1.2862N.
a) Arctan (f/g)) = arctan (1.2862/9.8) = 7.477 degrees.
b) The force is the same, so coefficient minimum = (f/g) = 1.2862/9.8, = 0.13.
Remember a coefficient is a ratio. It will hold true regardless of mass.
Force = mv^2/r, but when mass is not given, assume 1kg., = 9.8N.