Question about torque
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Question about torque

[From: ] [author: ] [Date: 12-12-23] [Hit: ]
03 = Fsin(53.4)*0.F = (2.03) / (sin(53.4)*0.x = Fsin(90)*0.......
A force is applied to a door at an angle of 53.4° and 0.26 m from the hinge.
(a) What force produces a torque with a magnitude of 2.03 N·m?
(b) How large is the maximum torque this force can exert?

It's the last problem and I cannot figure it out. Please help!

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(a) 2.03 = Fsin(53.4)*0.26

F = (2.03) / (sin(53.4)*0.26)

(b) Using the F from part a:

x = Fsin(90)*0.26
1
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