a sample of gas occupies 50.0L at 27 degrees Celsius. what will the volume be in liters of the gas at standard temperature??
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Combined Gas Law states: PV/T = PV/T. We can ignore pressure for this problem.
On the left you have 50L and 300.15K
On the right you have 273.15K (Standard Temp)
50L/300.15K = XL/273.15K
X=45.50224888L
With sig figs, your answer should be 45.5L
On the left you have 50L and 300.15K
On the right you have 273.15K (Standard Temp)
50L/300.15K = XL/273.15K
X=45.50224888L
With sig figs, your answer should be 45.5L
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grees Celsius. what will the volume be in liters of the gas at standard temperature?
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p1v1/t1 = p2v2/t2
since pressure isn't mentioned, let's leave that out.
v1/t1 = v2/t2
since what we want is v2, rearrange to
v1/(t2/t1) = v2
substituting in
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p1v1/t1 = p2v2/t2
since pressure isn't mentioned, let's leave that out.
v1/t1 = v2/t2
since what we want is v2, rearrange to
v1/(t2/t1) = v2
substituting in
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V(i)/T(i) = V(f)/T(f)
Vi = 50 L
Ti = 300 K
Tf= (if STP) 273 K or standard conditions --> 298 K
Therefore:
50/300 = V(f)/273K
45.5 L
Vi = 50 L
Ti = 300 K
Tf= (if STP) 273 K or standard conditions --> 298 K
Therefore:
50/300 = V(f)/273K
45.5 L