Calculate the concentration (mg/mL) of the protein in a cubic crystal with dimensions on each side of 0.5mm a

Calculate the concentration (mg/mL) of the protein in a cubic crystal with dimensions on each side of 0.5mm and density of 1.217g/cm3 and solvent content of %65 by weight

Any help would be greatly appreciated!! Thanks!

First you need the volume of the container, the volume of a cube is simply the side to the third power..

0,5 mm = 0,05 cm (0,05 cm)^3 = 0,05 cm x0,05 cm x0,05 cm = 0,000125 mL (cm3 = mL)

Now you use the density, if 1 mL contains 1,217 g of protein, how many grams will 0,000125 mL contain --> (0,000125 x 1,217) / 1 = 0,000152 g, and that number multiplied by 1000 renders the miligrams 0,152 mg.

The last thing to consider is that not all the solid content in the solution is protein, but rather 65% of it.

So, the real content of protein is = 0,65 x 0,152 mg = 0,0988 mg

And finally, we divide the mass in the volume = 0,0998 mg / 0,000125 mL = 790,4 mg/mL

Hope it helped