Number of atoms in 0.74 mol Sulfur

Please show your work.

Avogadros no.= 6.02E23 molecules/mole
0.74 moles S x 6.02E23= 4.45E23 atoms

No. of atoms = (total number of moles) x (Avogadro's constant)

No. of atoms = (total number of moles) x (6.023 x10^23)

In this case...

No. of atoms = (0.74) x (6.023 x10^23) = 4.46 x10^23 atoms