I think the answer would be, CuCl2 · H20 → Cu[2+] + 2Cl[-]. Does this look right? Did I miss anything?
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CuCl2(s) ---> Cu^2+(aq) + 2Cl^-(aq)
Generally speaking, the water of the solution is not shown in the equation nor is the water of hydration (in CuCl2 case, it is 2H2O, IIRC)
Generally speaking, the water of the solution is not shown in the equation nor is the water of hydration (in CuCl2 case, it is 2H2O, IIRC)