For the reaction shown, calculate how many moles of NH3 form when each of the following completely reacts? 3N2H4(l)-->4 NH3(g)+N2(g)
5.7x10^-2 mol N2H4
5.7x10^-2 mol N2H4
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3 N2H4 → 4 NH3 + N2
(5.7x10^-2 mol N2H4) x (4/3) = 7.6x10^-2 mol NH3
(5.7x10^-2 mol N2H4) x (4/3) = 7.6x10^-2 mol NH3