How do I get [Ag+] by itself

8.682=log(1/[Ag+]^2)

how do I get [Ag+] by itself? I'm really bad in math ): help please!

First raise both sides of the equation by a base of ten to get rid of the log.

10^8.682 = (1/[Ag+]^2)

Now multply both sides by [Ag+]^2

([Ag+]^2) * 10^8.682 = 1

Divide both sides by 10^8.682 and then take the square root of both sides ad you will have [Ag+] all alone.

[Ag+] = sqr(1/(10^8.682))

[Ag+] = 4.56*10^-5M

Take the negative log of the other side.

10^(8.682) = 1/[Ag+]^2

It's basic algebra after that.