Graham's law ...
( rate CH4 / rate SO2 ) ^2 = MM SO2 / MM CH4
= 64 / 16 = 4
so rate CH4 / rate SO2 = square root 4 = 2
CH4 diffuses 2 x as fast as SO2 .. this is expected since it is a much smaller molecule
( rate CH4 / rate SO2 ) ^2 = MM SO2 / MM CH4
= 64 / 16 = 4
so rate CH4 / rate SO2 = square root 4 = 2
CH4 diffuses 2 x as fast as SO2 .. this is expected since it is a much smaller molecule