How many nonmetal atoms are present in a 3.50 x 10–4 mole sample of potassium bicarbonate? I know that you have to find the molecular weight for potassium bicarbonate first...but then i am having trouble...please help!
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You actually don't have to find the molar mass.
To convert mols to atoms you have to use Avagadro's number, but before we do that, we have to determine the mols of nonmetal species. So in potassium bicarbonate (KHCO3), hydrogen, carbon and oxygen are nonmetals.
The number of mols of hydrogen to mols of potassium bicarbonate is 1 to 1, so there are 0.00035 mols of hydrogen.
The number of mols of carbon to mols of potassium bicarbonate is 1 to 1, so there are 0.00035 mols of carbon.
The number of mols of oxygen to mols of potassium bicarbonate is 3 to 1, so there are 0.00105 mols of oxygen.
That is a total of 0.00175 mols of nonmetals in 0.00035 mols of potassium bicarbonate.
Now multiply the total number of mols of nonmetals times Avagadro's number.
0.00175 mols * (6.022 x 10^23 atoms/mol) = 1.05 x 10^21 atoms of nonmetals
Hope this helped :)
To convert mols to atoms you have to use Avagadro's number, but before we do that, we have to determine the mols of nonmetal species. So in potassium bicarbonate (KHCO3), hydrogen, carbon and oxygen are nonmetals.
The number of mols of hydrogen to mols of potassium bicarbonate is 1 to 1, so there are 0.00035 mols of hydrogen.
The number of mols of carbon to mols of potassium bicarbonate is 1 to 1, so there are 0.00035 mols of carbon.
The number of mols of oxygen to mols of potassium bicarbonate is 3 to 1, so there are 0.00105 mols of oxygen.
That is a total of 0.00175 mols of nonmetals in 0.00035 mols of potassium bicarbonate.
Now multiply the total number of mols of nonmetals times Avagadro's number.
0.00175 mols * (6.022 x 10^23 atoms/mol) = 1.05 x 10^21 atoms of nonmetals
Hope this helped :)
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KHCO3 is potasium bicarbonate.
1 mole of KHCO3 contains 1 mole of K, 1 mole of H, 1 mole of C, and 3 moles of O.
So we have 6 moles of nonmetal atoms (H, C, O) per 1 mole of KHCO3.
3.50 x 10^-4 moles KHCO3 x (6 moles nonmetal atoms / 1 mole KHCO3) x (6.02 x 10^23 atoms / 1 mole of atoms) = 1.26 x `10^22 atoms
1 mole of KHCO3 contains 1 mole of K, 1 mole of H, 1 mole of C, and 3 moles of O.
So we have 6 moles of nonmetal atoms (H, C, O) per 1 mole of KHCO3.
3.50 x 10^-4 moles KHCO3 x (6 moles nonmetal atoms / 1 mole KHCO3) x (6.02 x 10^23 atoms / 1 mole of atoms) = 1.26 x `10^22 atoms