How do you solve this chemistry equation

Calculate the mass of LiNO3 needed to make up the following solution to the correct # of sig figs:

25 mL of 2.0 M LiNO3 g

Please just give me a straight out x/y times z=answer
I asked my friend for help, but when I asked something proving what she said to do wrong she just called me stupid saying she'd already explained it to me -.-
Meh, realized a long time ago she wasn't the best friend =/

First you have to realize what your solution has in it.
Molarity (M) = mols/liters.
Therefore, if you have 2M LiNO3, but only 25ml, you have to covert 25ml to L

25ml (1L/1000ml) = 25/1000 = 0.025L

Now: 2M =X mols/0.025L
Solve for X.
2 = x/0.025
x = 2(.025) = 0.05 mols LiNO3 in solution.

Next, what's the molar mass of LiNO3??? http://www.ptable.com
7+14+(16x3) = 69g/mol, therefore you have 3.45 grams (=69*0.05) of LiNO3 in solution.

Easy, huh?
Good luck!