Let the random variable X denote the number of girls in a five-child family. If the probability of a female birth is 0.5, find the following probabilities.
(a) Find the probability of 0, 1, 2, 3, 4, and 5 girls in a five-child family. (Round your answers to three decimal places.)
P(0 girls) =
P(1 girl) =
P(2 girls) =
P(3 girls) =
P(4 girls) =
P(5 girls) =
Please help me solve this!
(a) Find the probability of 0, 1, 2, 3, 4, and 5 girls in a five-child family. (Round your answers to three decimal places.)
P(0 girls) =
P(1 girl) =
P(2 girls) =
P(3 girls) =
P(4 girls) =
P(5 girls) =
Please help me solve this!
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n = 5; p = 0.5; q = 0.5; P(x = 5) = nCx p^x (1-p)^(n-x)
μ = (n p) = 2.5; σ² = ( n p q ) = 1.25; σ = √( n p q ) = 1.118033989
x P(x) ΣP(x) 1-ΣP(x)
--- --------- --------- ---------
0 0.0312500 0.0312500 0.9687500
1 0.1562500 0.1875000 0.8125000
2 0.3125000 0.5000000 0.5000000
3 0.3125000 0.8125000 0.1875000
4 0.1562500 0.9687500 0.0312500
5 0.0312500 1.0000000 0.0000000
μ = (n p) = 2.5; σ² = ( n p q ) = 1.25; σ = √( n p q ) = 1.118033989
x P(x) ΣP(x) 1-ΣP(x)
--- --------- --------- ---------
0 0.0312500 0.0312500 0.9687500
1 0.1562500 0.1875000 0.8125000
2 0.3125000 0.5000000 0.5000000
3 0.3125000 0.8125000 0.1875000
4 0.1562500 0.9687500 0.0312500
5 0.0312500 1.0000000 0.0000000