"The solubility of PbCl2 is 1.6x10^(-2) mol/L. What is the Ksp of PbCl2?" The answer is 1.6x10^(-5).
I always have trouble with these problems, the ones with formulas that are just AB --> A + B, with no coefficients. I have no idea why, but I always get them wrong. Please help me figure this out!!
I always have trouble with these problems, the ones with formulas that are just AB --> A + B, with no coefficients. I have no idea why, but I always get them wrong. Please help me figure this out!!
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PbCl2 ---> Pb^2+ + 2Cl^-
Ksp = [Pb^2+] [Cl^-]^2
Ksp = (1.6x10^(-2)) (3.2x10^(-2))^2
Ksp = 1.64 x 10^-5
More:
http://www.chemteam.info/Equilibrium/Cal…
The second example is CaF2, which is analogous to PbCl2
Ksp = [Pb^2+] [Cl^-]^2
Ksp = (1.6x10^(-2)) (3.2x10^(-2))^2
Ksp = 1.64 x 10^-5
More:
http://www.chemteam.info/Equilibrium/Cal…
The second example is CaF2, which is analogous to PbCl2