What is the pH of a 0.06 M Ba(OH)2 aqueous solution

can you show me how to do it? :)
thanks

One mole of Ba(OH)2(aq) Forms: 1 mole of Ba2+(aq) and 2 moles of OH-(aq)
OH-ions = 2 x .06 = 0.12 moles = 1.2x10^-1
pOH = 0.92 pH = 14.00 - 0.92 = 13.08