Calculate Delta H rxn for photosynthesis

Balanced formula I came up with...
6CO2(g) + 6H2O(l) --> C6H12O6(s) + 6O2 (g)

It's now asking me to calculate the Delta H rxn??

/\ H rxn = ___________ kJ

need ∆Hformation H2O, CO2 and glucose

∆H formation H2O = -285.8kJ/mole
∆H formation CO2 = -393.5kJ/mole
∆H formation C6H12O6 = -1273.3kJ/mole

∆H rxn = products - reactants.....remember to use the balanced equation to get the moles of each reactant and product.

∆H rxn = (-1273.3) - (6 x -393.5 + 6 x -285.8) = 2802.5kJ, endothermic