How do you find the length of sides of a cube given density and mass

I am given 5.4* 10^-4 Kg/cm^3 and a mass of 78 g, what are the steps to finding the length of the sides? And do I use the V=m/D at any point?



Thanks in advance!

The key to stuff like this is to look at the units. Notice how you have a dimension's unit in the denominator? Since it is in the denominator that is a clue to get your answer by divide using it. So, Density = Mass / Volume
Volume = Mass/Density (kg/(kg/cm^3)) = (cm^3)

0.078kg/5.4*10^-4kg/cm^3 = 144.4cm^3

Take the cubic root of this for one side...

5.25

Interesting question. I'll give it a shot. (So don't assume I'm correct...)
The way I planned it, first covert density into g/cm³:
Density = .54 g/cm³
So now, if you have 78g of mass then find out how many cm³ you have,
so yes use V = m/D:
V = 144.4444cm³
Since you have a cube, its easy to find a side (s), use the formula: Volume of cube = s³
so; s = ³√V = ³√(144.4444cm³) ≈ 5.246869722 cm
And that's what I got

Density = mass/volume, so volume = mass / density

But you have to be careful with units - work in just kg or just g, but dont mix them.

Volume = ( 78/1000 ) / 5.4 x 10^-4 = 144.44 cm3

Cube root of the volume gives you 5.25 cm, which is the length of the sides.

densty = mass/ volume [mass per unit volume is density ]
or d = m/ v
or v=m/d= 78/5.4*10^-1
= 780/5.4 =144.444444
also volume of cube = (side)^3
so side = ( 144.444444)^1/3
= 5.24 cm answer ----------------------------------------… PROOF---------------
v= 144.44
m = 78 gm
so d = m/v = 78/144.44 = 0. 54 gm/cm^3
= 0.54/1000 Kg/cm^3
= 5.4 * 10^-4 Kg/cm^3 =given

D=5.4*10^-4kg/cm3i.e 5.4*10-1g/cm3 M=78gi.e0.078kg since v=m/D , v=0.078/5.4*10-1=0.144cm3 since volume of a cube=L3,then 0.144cm^3=L^3...... L=0.144^(1/3)...........ANS:L=0.52cm