Charles Law Help - A gas has T=27.00C in a 10.0L vessel....
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Charles Law Help - A gas has T=27.00C in a 10.0L vessel....

[From: ] [author: ] [Date: 11-11-26] [Hit: ]
T2 = 600.3 / 10 = 60.03K - 273 = -213.12°C.This is CHARLESLAW: and is defined as :-The volume of a given mass of gas, is directly proportional to its absolute temperature,......
It is forced at constant n and P into a 2.00x10^3 mL vessel. What is the new temp in celsius?

The answer I got was -213.2 Celsius.

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V1T2 = V2T1
10L x T2 = 2L x 300.15K
T2 = 600.3 / 10 = 60.03K - 273 = -213.12°C.

This is CHARLES' LAW : and is defined as :- 'The volume of a given mass of gas, is directly proportional to its absolute temperature, when its pressure remains constant'.

This calculation isn't limited to Kelvin Temperature which is associated with Celsius.
We can also use Rankine (R) absolute temperature associated with Fahrenheit. calories and Btu are alsu used as Heat units if required.

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you did everything correct but you forgot to change C to Kelvin. You can only use Kelvin when doing anything with gases.
K = C +273
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