Help please specific heat
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Help please specific heat

[From: ] [author: ] [Date: 11-10-20] [Hit: ]
96=0.The metal is titanium Ti(see my link)atomic mass 47.......
a metal sample weighing 44.625 grams and at a temperature of 100.00 C was placed in 35.278 grams of water contained in a calorimeter at 24.74 C. at equilibrium, the temperature of the water and metal was 34.97 C. what is the specific heat of the metal ? what is the approximate atomic weight of the metal ?

specific heat = ________________

atomic weight = _______________

-
you write the energy lost by the matal (Em) is given to the water(Ew)
formula E=mc(tf-ti)

Em = 44.625*c(m) *(34.97-100)= -2901.96*c(m)
Ew= 35.278*4.184*(34.97-24.74)=1509.98 J
you write that the absolute values for Em and Ew are equal

so c(m) = 1509.98/2901.96=0.52J/°K/g

The metal is titanium Ti (see my link) atomic mass 47.857
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