P4, KF, C6H6, or Br2 ?
And please briefly explain why ..
It's on my exam review.
And please briefly explain why ..
It's on my exam review.
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Keep in mind that there are no 100% ionic bonds in compounds. We prefer to classify bonds by their percent ionic character (PIC). The percent ionic character is a function of the electronegativity difference. The greater the EN difference, the greater the percent ionic character.
In your case the greatest percent ionic character will be for KF.
PIC = 100 [ 1 - e^-(DEN^2/4) ]
In your case the greatest percent ionic character will be for KF.
PIC = 100 [ 1 - e^-(DEN^2/4) ]
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KF