How long seven astronauts will be save before the LiOH runs out
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How long seven astronauts will be save before the LiOH runs out

[From: ] [author: ] [Date: 11-05-24] [Hit: ]
The 2 comes from the number of moles of LiOH there.Another way of putting it is that the number of moles of CO2 reacting is 1/2 the number of moles of LiOH reacting.44.0096 is the molecular mass of CO2.......
CO2 produced by astronauts on space mission needs to be eliminated from the air as it is detrimental to the astronauts. Engineers created a device that reacts the CO2 with LiOH to produce Li2CO3. Columbia Mission has failed and a rescue mission has been organized. If there is only 213 kg of LiOH on board, how long does the rescue crew have to save the 7 astronauts before the LiOH runs out? (1kg CO2 produced/day/astronaut) PLEASE PLEASE SHOW all your calculations and works PLEASEEE. THX FOR YOUR VALUABLE TIME! peace!

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CO2 + 2 LiOH → H2O + Li2CO3

(213 kg LiOH) / (23.9486 g LiOH/mol) x (1/2) x (44.0096 g/mol) = 195.7 kg CO2

(195.7 kg)/ (7 kg/day) = 28 days

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The 1 in the 1/2 comes from the number of moles of CO2 in the balanced equation. The 2 comes from the number of moles of LiOH there. Another way of putting it is that the number of moles of CO2 reacting is 1/2 the number of moles of LiOH reacting.
44.0096 is the molecular mass of CO2.

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