Calculate the deBroglie wavelength of a shot gun pellet weighing 1.2 g moving with a velocity of 334.8 miles per hour ? What units do I need to convert 334.8 to m/s?? Any help would be greatly appreciated.
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The formula is: deBroglie wavelength (lambda) = h / mv
h is Planck's constant. h = 6.63 ×10−34 J s
The mass and speed must be in standard physics units.
You'll get lambda in the standard wavelength unit, meters.
The mass must be in kg: 1.2 g = 0.0012 kg
(shortcut g to kg: move decimal point 3 places to the left)
To convert mi/h to m/s, use these conversions:
1 h = 3600 s
1 mi = 1610 m
The set-up: 334.8 mi/h x 1 h/3600 s x 1610 m/1 mi
Just do the math to get the speed in m/s.
Notice that in the second factor the 1 h is put on top to cancel out the h unit in the bottom of the mi/h.
Notice that in the third factor the 1 mi is put on bottom to cancel out the mi unit in the top of the mi/h.
h is Planck's constant. h = 6.63 ×10−34 J s
The mass and speed must be in standard physics units.
You'll get lambda in the standard wavelength unit, meters.
The mass must be in kg: 1.2 g = 0.0012 kg
(shortcut g to kg: move decimal point 3 places to the left)
To convert mi/h to m/s, use these conversions:
1 h = 3600 s
1 mi = 1610 m
The set-up: 334.8 mi/h x 1 h/3600 s x 1610 m/1 mi
Just do the math to get the speed in m/s.
Notice that in the second factor the 1 h is put on top to cancel out the h unit in the bottom of the mi/h.
Notice that in the third factor the 1 mi is put on bottom to cancel out the mi unit in the top of the mi/h.