Can some one PLZ help me with Chemistry

Benzene = Boiling point (80.1 °C) Kb (2.53 °C/m)
Freezing Point (5.5°C) Kf (5.12 °C/m)
1.49 m of naphthalene (C10H8) in benzene
What is the Boiling point and Freezing?

Freezing point elevation and boiling point depression have the same form of equation

deltaT = m.K

b.p.: deltaT = 1.49 x 2.53 = 3.77 °C and bp = 80.1 + 3.77 = 83.9 °C

f.p.: deltaT = 1.49 x 5.12 = 7.63 °C and fp = 5.5 - 7.63 = -2.1 °C

...what you already wrote Benzene = Boiling point (80.1 °C) Kb (2.53 °C/m)
Freezing Point (5.5°C) Kf (5.12 °C/m)