A rice breeder obtained a triple heterozygote carrying the three recessive alleles for albino flowers (al), brown awns (b), and fuzzy leaves (fu), all paired with their normal wild-type alleles. This triple heterozygote was testcrossed. The progeny phenotypes were
170 wild type
150 albino, brown, fuzzy
5 brown
3 albino, fuzzy
710 albino
698 brown, fuzzy
42 fuzzy
38 albino brown
a. Are any of the genes linked? If so, draw a map labeled with map distances. (Don’t bother with a correction for multiple crossovers.)
So I have to find the recombinants...for each
170+150+5+3 =328 recombinants between al and fu
42+38 + 5+3 = 88 recombinants between fu and b
I don't understand.. why those numbers?? HOW can you determine whats between al and fu or fu and b ???? I made a table but I don't get it.. which number do I have to chose..? what do they mean by between al-fu and fu-b ??
thats all
thanks
170 wild type
150 albino, brown, fuzzy
5 brown
3 albino, fuzzy
710 albino
698 brown, fuzzy
42 fuzzy
38 albino brown
a. Are any of the genes linked? If so, draw a map labeled with map distances. (Don’t bother with a correction for multiple crossovers.)
So I have to find the recombinants...for each
170+150+5+3 =328 recombinants between al and fu
42+38 + 5+3 = 88 recombinants between fu and b
I don't understand.. why those numbers?? HOW can you determine whats between al and fu or fu and b ???? I made a table but I don't get it.. which number do I have to chose..? what do they mean by between al-fu and fu-b ??
thats all
thanks
-
the recombinants are the ones that are not parental...so for example between al and fu, u have to select the progeny numbers that dont have al/fu+ and al+/fu (the parentals) ... so you get 5+3+42+38=88