Help please?
A spring is used to launch a ball with a mass of 1.00 x 10^-2 kg. The spring is compressed 10.0cm using an average force of 35.0 N. For a launch, the ball is placed against the movable end of the spring and the compressed spring is released What is the work done in compressing the spring? A)0.350 J B)3.50...
-------------------------------------------------------
answers:
electron1 say: Work = Average force * distance = 35 * 0.1 = 3.5 J
B is the correct answer.
-
oubaas say: work W = F*x = 35 N * 0.1 m = 3.5 N*m (joule)
-
Donald say: cnxfsuma
-
nubjj say: zasxaypp
-
Lena say: xzhwyxmf
-
isaqw say: mosyicuc
-
oguyy say: lrvfdfjr
-
qaoos say: lzjfbnnx
-
eczbj say: klwfzobq
-
lyjyw say: iqucdnkj
-
electron1 say: Work = Average force * distance = 35 * 0.1 = 3.5 J
B is the correct answer.
-
Andrew Smith say: Work = Force * distance where the force is in Newtons and the distance is in metres
10 cm -> 0.1m and the average force is 35 N
so the work = 35 * 0.1 = 3.5 J
-
say: All values in SI units:
average force = 35.0N
distance = 10.0cm = 0.100m
Work = average force x distance
= 35.0 x 0.100
= 3.50J (answer B).
Happy New Year!
-
Ash say: W = Fx = (35.0 N)(0.100 m) = 3.50 J
-