A 63-kg person on skis starts from rest down a hill sloped at 37° from the horizontal. The coefficient of friction between the skis and...?
After the skier had been moving for 5.0 s, the friction of the snow suddenly increased and made the net force on the skier zero. What is the new coefficient of friction?
How fast would the skier now be going after skiing for another 5.0 s?
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answers:
oubaas say: μ = tan 37° = 0.75
final speed Vf equal to the unknown initial speed Vi
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BigBird say: If the net force is zero, then there is no acceleration and his speed does not change during the second 5 seconds Your problem statement does not give enough data to determine the speed. With the new coefficient the horizontal components of the forces must add to zero: N*sin(37) - u*N*cos(37) =0 then u = tan(37)
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