1)How much must a 1.0 kg squirrel change its potential energy to get from the ground to the top of a 15m tall tree?
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answers:
derfram say: PE = mgh
PE = 1.0 kg * 9.8 m/s² * 15 m = 147 kg-m²/s² = 147 J
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oubaas say: 1
U = m*g*h = 9.8*1*15 = 147 joule
2
final squared speed Vf^2 = Vo^2+2*g*Δh = 8^2+2*25*9.8 = 554 m^2/sec^2
final kinetic energy Ekf = m/2*Vf^2 = 0.5*554 = 277 joule
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derfram say: PE = mgh
PE = 1.0 kg * 9.8 m/s² * 15 m = 147 kg-m²/s² = 147 J
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