As more bulbs are connected in series in a circuit, what happens to the current leaving the source?

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answers:
frank lynn say: As more lamps are installed in the series circuit, the current decrease due to the increase in resistance in the circuit per Ohm's Law.
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oubaas say: the higher the quantity of the bulbs , the lower the current flowing through the circuit (provided the supply voltage doesn't change)
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JosephV say: As more bulbs are connected in series, the resistance offered will add.
R (total) = R1 + R2 + etc.
Using the equation derived from Ohms Law
E = IR
When R (ohms) increases, I (amperes) decreases at a constant value for E (volts)
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electron1 say: As more bulbs are connected in series in a circuit, the resistance will increase. This will cause the current to decrease. Let me give you an example. A 12 volt battery has two four ohm light bulbs. Let’s use the following equation to determine the current.

I = V ÷ R
I = 12 ÷ (4 + 4) = 1.5 amps

Let’s add one more four ohm light bulb.

I = 12 ÷ (4 + 4 + 4) = 1 amp.

I hope this is helpful for you.
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Vaman say: reduces.
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roger say: since the resistance goes up the current will decrease.
I=E/R as R goes up I will decrease.
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