centripetal force question?
A 200 g ball on the end of a string is rotated in a horizontal circle of radius 10 m. The ball completes 10 rotations in 5 s. What is the centripetal force of the string on the ball?
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answers:
electron1 say: Fc = m * v^2 ÷ r
m = 0.2 kg

During one rotation, the ball moves a distance that is equal to the circumference of the horizontal circle.

d = 2 * π * 10 = 20 * π
Total distance = 10 * 20 * π = 200 * π
v = 200 * π ÷ 5 = 40 * π

This is approximately 126 m/s.

Fc = 0.2 * (40 * π)^2 ÷ 10 = 32 * π^2
This is approximately 316 N. I hope this is helpful for you.
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billrussell42 say: Centripetal force f = mV²/r = mrω²
ω is angular velocity in radians/sec
1 radian/sec = 9.55 rev/min
m is mass in kg
r is radius of circle in meters
V is the tangental velocity in m/s = ωr
f is in Newtons

A 200 g ball on the end of a string is rotated in a horizontal circle of radius 10 m. The ball completes 10 rotations in 5 s. What is the centripetal force of the string on the ball?

10 rev/5 s = 2 rev/s
2 rev/s x 2π rad/rev = 4π rad/s
f = mrω² = 0.2 kg x 10 m x 4π rad/s = 8π N
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