A string 1 meter long is used to whirl a 0.5 kg mass in a vertical circle at a constant speed of 5m/s. what is the tension in the string when the object is at the side, top, and bottom of the circle?
How do I do this????
How do I do this????
-
First compute the radial acceleration:
Ar = V²/r = 5²/1 = 25 m/s²
Then,
Add in gravitational acceleration:
a) At the top: Atot = Ar - g = 15.2 m/s² → T = m*Atot = 0.5*15.2 = 7.6 N
b) At side: Atot = Ar = 25 → T = m*Ar = 12.5 N
c) At bottom: Atot = Ar + g = 34.8 m/s² → T = 0.5*34.8 = 17.4 N
Ar = V²/r = 5²/1 = 25 m/s²
Then,
Add in gravitational acceleration:
a) At the top: Atot = Ar - g = 15.2 m/s² → T = m*Atot = 0.5*15.2 = 7.6 N
b) At side: Atot = Ar = 25 → T = m*Ar = 12.5 N
c) At bottom: Atot = Ar + g = 34.8 m/s² → T = 0.5*34.8 = 17.4 N