Two boys are playing in the snow in the diagram below. One boy is standing on the edge of the roof while the other is 3.75 m underneath the first. The boy on the ground runs forward at 5.20 m/s. The boy on the roof can throw a snowball at 8.50 m/s.
(a) At what angle should the boy on the roof throw the snowball so that it hits the running boy on the top of his head?
(b) What distance x did the boy get to?
(c) How long was the snowball in the air?
heres a link to the question, its question 2 and it has a diagram
http://www.kwantlen.bc.ca/science/physic…
Please help, he does not provide answers and i don't know how to approach this question, seems to me its a "chase question so i think you must set constraints and such"
(a) At what angle should the boy on the roof throw the snowball so that it hits the running boy on the top of his head?
(b) What distance x did the boy get to?
(c) How long was the snowball in the air?
heres a link to the question, its question 2 and it has a diagram
http://www.kwantlen.bc.ca/science/physic…
Please help, he does not provide answers and i don't know how to approach this question, seems to me its a "chase question so i think you must set constraints and such"
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(a).
analyzing for the first boy,
x = vt
x = (5.2)t
t = x/5.2
analyzing for the second one,
x = Vo t cos Φ
t = x/(Vo cos Φ)
x/5.2 = x/(Vo cos Φ)
Vo cos Φ = 5.2
8.5 cos Φ = 5.2
cos Φ = 0.611765
Φ = 52.28°
(b).
y = Vo t sin Φ + ½ g t²
-3.75 = 8.5 t sin 52.28° + ½ (-9.8) t²
choose positive value for t,
t = 1.79784 sec
x = Vo t cos Φ
x = (8.5)(1.79784) cos 52.28°
x = 9.34936 m
(c).
based on the answer at (b) part, t = 1.79784 sec
analyzing for the first boy,
x = vt
x = (5.2)t
t = x/5.2
analyzing for the second one,
x = Vo t cos Φ
t = x/(Vo cos Φ)
x/5.2 = x/(Vo cos Φ)
Vo cos Φ = 5.2
8.5 cos Φ = 5.2
cos Φ = 0.611765
Φ = 52.28°
(b).
y = Vo t sin Φ + ½ g t²
-3.75 = 8.5 t sin 52.28° + ½ (-9.8) t²
choose positive value for t,
t = 1.79784 sec
x = Vo t cos Φ
x = (8.5)(1.79784) cos 52.28°
x = 9.34936 m
(c).
based on the answer at (b) part, t = 1.79784 sec