A 10kg block lies to the left of a 5kg block. If the 10kg block is pushed with a force of 30 Newtons...
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A 10kg block lies to the left of a 5kg block. If the 10kg block is pushed with a force of 30 Newtons...

[From: ] [author: ] [Date: 12-06-04] [Hit: ]
It would also have been more consistent and easier to understand the question if it had said lies to the west of... - tell your teacher or textbook to get his/its act together!Acceleration is simply a = F/m = 30/15 = 2 m/s/s, and the direction will be in the same direction the force is acting,......
A 10kg block lies to the left of a 5kg block. If the 10kg block is pushed with a force of 30 Newtons at an angle of 30 degrees South of East:

a) determine the net acceleration of the system.

b) find the contact force (magnitude and direction) of the 5kg mass on the 10kg mass.

-
(We have to assume a frictionless surface, since no coefficients are given. It would also have been more consistent and easier to understand the question if it had said 'lies to the west of...' - tell your teacher or textbook to get his/its act together!)

Acceleration is simply a = F/m = 30/15 = 2 m/s/s, and the direction will be in the same direction the force is acting, since there are no other forces acting.

The 5 kg mass is accelerating at 2 m/s/s so the force causing it to accelerate (the force between the blocks) is simply F = ma = 5*2 = 10 N.

This is the force of the 10 kg block on the 5 kg block, accelerating it in the E-30-S direction, but Newton's third law tells us the force of the 5 kg block on the 10 kg block will have the same magnitude and the opposite direction. So its magnitude is 10 N and its direction is 30 degrees north of west.

(a diagram would, as always, be very helpful)
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