What is the probability that a five card hand dealt from a standard deck of cards will include four cards of the same value?
Can someone please answer it with the steps of how to do the question
if it helps the answer is 1/4165
Can someone please answer it with the steps of how to do the question
if it helps the answer is 1/4165
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Lulu -
There are 13 cards (A, K, Q, ..., 2), so choose one of them to be the 4 matching cards. There are 13C1 = 13 ways to do that.
Next, we need to pick the 5th card and there are 52 - 4 = 48 to pick from, So, there are 48C1 = 48 ways to pick the 5th card.
In total, the Numerator = 13 x 48 = 624
Now, the Denominator = 52C5 = 2,598,960
P = 624 / 2,598,960 = 1/4165
Hope that helps
There are 13 cards (A, K, Q, ..., 2), so choose one of them to be the 4 matching cards. There are 13C1 = 13 ways to do that.
Next, we need to pick the 5th card and there are 52 - 4 = 48 to pick from, So, there are 48C1 = 48 ways to pick the 5th card.
In total, the Numerator = 13 x 48 = 624
Now, the Denominator = 52C5 = 2,598,960
P = 624 / 2,598,960 = 1/4165
Hope that helps