A 92.3 kg basketball player can leap straight up in the air to a height of 73.7 cm, as shown below. The player bends his legs until the upper part of his body is dropped by 67.2 cm, then he begins his jump. With what speed must the player leave the ground to reach a height of 73.7 cm?
Suppose the player jumps while standing on a bathroom scale that reads in newtons. What does the scale read before he begins his jump? What does the scale read after his feet leave the ground?
Suppose the player jumps while standing on a bathroom scale that reads in newtons. What does the scale read before he begins his jump? What does the scale read after his feet leave the ground?
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V = √[2gy] = √[2*9.8*0.737] = 3.8 m/s
W1 = m*g = 904.5 N
W2 = 0
W1 = m*g = 904.5 N
W2 = 0