Light is incident normally on the short face of a 30 degrees-60 degrees-90 degrees prism (see the figure ). A drop of liquid is placed on the hypotenuse of the prism.
http://session.masteringphysics.com/prob…
If the index of the prism is 1.67, find the maximum index that the liquid may have if the light is to be totally reflected.
10 points for correct answer.
http://session.masteringphysics.com/prob…
If the index of the prism is 1.67, find the maximum index that the liquid may have if the light is to be totally reflected.
10 points for correct answer.
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The light strikes the hypotenuse at an internal angle of incidence = 60º .. this is to be the critical angle with the ray continuing along the hypotenuse in the liquid (refractive index = N)
Applying n.sin i = constant at this boundary..
1.67 sin 60 = N.sin 90 .. (sin 90 = 1)
N = 1.67 sin 60 .. .. .. ►N = 1.45
Applying n.sin i = constant at this boundary..
1.67 sin 60 = N.sin 90 .. (sin 90 = 1)
N = 1.67 sin 60 .. .. .. ►N = 1.45