In a physics lab experiment, a spring clamped to the table shoots a 19 g ball horizontally. When the spring is compressed 22 cm, the ball travels horizontally 4.9 m and lands on the floor 1.6 m below the point at which it left the spring.
What is the spring constant?
Express your answer using two significant figures.
thanks!!
What is the spring constant?
Express your answer using two significant figures.
thanks!!
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Potential Energy of Spring = (1/2) k x^2 = (1/2) k (0.22)^2
= Initial Kinetic Energy of Ball = (1/2) m v^2 = (1/2) (0.019) (Vh)^2
therefore, k = 0.3926 (Vh)^2 where Vh is the speed of the ball in the horizontal dimension.
To find Vh we must first determine the time that the ball is in the air for...
distance = (1/2) a t^2 where a = g = 9.8 m/s^2 and distance = 1.6 m
therefore, t = sqrt{ 2 * 1.6 / 9.8 } = 0.5714 seconds
Vh = distance / time = 4.9 / 0.5714 = 8.575 m/s
now we can use our previous equation!
k = 0.3926 (Vh)^2 = 0.3926 * (8.575) ^ 2
= 29
= Initial Kinetic Energy of Ball = (1/2) m v^2 = (1/2) (0.019) (Vh)^2
therefore, k = 0.3926 (Vh)^2 where Vh is the speed of the ball in the horizontal dimension.
To find Vh we must first determine the time that the ball is in the air for...
distance = (1/2) a t^2 where a = g = 9.8 m/s^2 and distance = 1.6 m
therefore, t = sqrt{ 2 * 1.6 / 9.8 } = 0.5714 seconds
Vh = distance / time = 4.9 / 0.5714 = 8.575 m/s
now we can use our previous equation!
k = 0.3926 (Vh)^2 = 0.3926 * (8.575) ^ 2
= 29