Two forces F1 and F2 act on a 9.20-kg object. Physics help, please!
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Two forces F1 and F2 act on a 9.20-kg object. Physics help, please!

[From: ] [author: ] [Date: 11-09-27] [Hit: ]
Adding,Magnitude of the force = sqrt(36^2 + (6^2)*3) = sqrt(1296 + 108) = sqrt(1404) = 37.Direction = tan inverse of (6*sqrt(3)/36) = tan inverse of (sqrt(3)/6) = 16.102 degrees.Force = mass * acceleration,.......
Two forces F1 and F2 act on a 9.20-kg object. F1 = 30.0 N and F2 = 12.0 N.

Determine the magnitude and the direction of the acceleration if the angle between F1 (horizontal line) and F2 (slanted line) is 60 degrees.

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F1 = 30i + 0j

F2 = 12*cos 60 i + 12*sin 60 j
= 6i + 6*sqrt(3) j

Adding, the final force is 36i + 6*sqrt(3)j

Magnitude of the force = sqrt(36^2 + (6^2)*3) = sqrt(1296 + 108) = sqrt(1404) = 37.4699

Direction = tan inverse of (6*sqrt(3)/36) = tan inverse of (sqrt(3)/6) = 16.102 degrees.

Force = mass * acceleration,
.'. a = F/m = 37.4699/9.2 = 4.072m/s in a direction of 16.102 degrees from the horizontal.
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