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Physics helps plsease

[From: ] [author: ] [Date: 11-05-18] [Hit: ]
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Final velocity = (Final vertical velocity^2 + Final horizontal velocity^2)^0.5

Tangent of angle above horizontal = (Final vertical velocity) ÷ Final horizontal velocity

(a) What is the vertical component of its initial velocity =
(b) What is the horizontal component of its initial velocity?
(c) What was its maximum height above its launch point?
(d) As it hits the hill, what speed did it have and what angle did its velocity make with the vertical?

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For "Y" component of original Velocity use equation: Y = InitialVelocity x Cos(theta)
For "X" component of original velocity use equation : X = InitialVelocity x Sin(theta)
Maximum height = Yvelocity x Time + 1/2 x Ag x Timesquared
Speed at any point in trajectory = Square root of(Xvelocitysquared + Yvelocitysquared)
Angle at any point in trajectory = inversetangent(Yvelocity/Xvelocity)
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