The radius of Jupiter is about 72.0 × 10^3 km. The radius of the Earth is about 6300.0 km?
How many Earth volumes would fit inside Jupiter's volume?
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answers:
Mike G say: Linear Scale J/E = 72,000/6300 = 720/63 = 80/7
Volume Scale = (80/7)^3 = 1492.7
Answer 1493
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Iggy Rocko say: volume of Jupiter / volume of earth =
[4pi(72000)^3/3]/[4pi(6300)^3/3] =
72000^3/6300^3 =
720^3/63^3 =
1492.7
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Ian H say: Ratio of radii, cubed.
(72000/6300)^3 = (80/7)^3 ~ 1492
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Como say: :--

72000 / 6300 = 720 / 63 = 80 / 7

80/7 = 14______to nearest whole number
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az_lender say: If you could deform the earth, the number of earths that would fit inside Jupiter would be around (72000/6300)^3 = (80/7)^3 = 1492.

If the earth remained a sphere, the number that would fit inside Jupiter would be about 1100.
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Jeff Aaron say: (72000/6300)^3 =~ 1492.7113702623906705539358600583
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say: Wait doesn’t volume only apply to 3D things?
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alex say: Rj / Re = 11.4 --->Vj / Ve = 1481
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