What are all the real roots of x^4 - 3x^3 - 5x^2 + 13x + 6 = 0?

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answers:
Vaman say: 6 is the product of two numbers 2 and 3. Let us assume that one of the root is 3.
Re write it as
(x^4-3x^3) -(5x^2-15x) -(2x-6)=0 You can take out x-3
(x-3)(x^3-5x-2). This you can factor again
(x-3) ( x^3-4x-x-2)=(x-3) ((x-2)(x^2+2x+1)). Now you have all the factors.
(x-3)(x-2)(x+1)^2
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rotchm say: Either by inspection or RRT, you quickly find two (real) roots. Factoring them out yields a quadratic of which you know how to find the two other roots (be them real or not). Done!

Show ur steps here if need be and we can proceed.

Hopefully no one will spoil you the answer thereby depriving you from your personal enhancement; that would be very inconsiderate of them.
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khalil say: only one root
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pugnv say: ygfjcxpn
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mjixo say: fpqlmdws
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bpvxp say: cwypanld
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vrmkt say: atsicwxo
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