Exact value root of f(x)= 5x^2 + 12x  5?

answers:
sepia say: f(x) = 5x^2 + 12x  5
x = 6/5  sqrt(61)/5
x = sqrt(61)/5  6/5

la console say: 5x² + 12x  5 = 0
5x² + 12x = 5
x² + (12/5).x = 1
x² + (12/5).x + (6/5)² = 1 + (6/5)²
x² + (12/5).x + (6/5)² = (25/25) + (36/25)
x² + (12/5).x + (6/5)² = 61/25
[x + (6/5)]² = [± (√61)/5]²
x + (6/5) = ± (√61)/5
x =  (6/5) ± [(√61)/5]
x = ( 6 ± √61)/5
x₁ = ( 6 + √61)/5
x₂ = ( 6  √61)/5

Morningfox say: The standard quadratic equation will work here (like it does for ALL quadratic equations).
root = [b +/ sqrt( b^2  4ac) ] / ( 2a)
root = [12 +/ sqrt( 12^2  4*5*(5)) ] / ( 2(5))
root = 1.2 +/ 0.2 sqrt( 61)

RealPro say: Yeah that makes no sense so you should explain the question better.

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