Determine the intersection point of the graphs of y= 5log(x-3) and y= -logx + 3
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Ok, if you make these two = to each other you have
5*log(x-3) + log(x) = 3
now from properties of logs this converts to log[(x-3)^5*x] = 3.
And taking both sides as exponents of 10 we have x*(x-3)^5 = 1000
and the answer is x is 5.800 aproximately. You have to solve it graphically using Graph 4.4
5*log(x-3) + log(x) = 3
now from properties of logs this converts to log[(x-3)^5*x] = 3.
And taking both sides as exponents of 10 we have x*(x-3)^5 = 1000
and the answer is x is 5.800 aproximately. You have to solve it graphically using Graph 4.4
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5log(x-3) = -log(x) + 3
exp(5)(x-3) = -x + exp(3)
x - 3 + x = exp(3)/exp(5)
x = exp(-2)/2 + 3/2
Insert into either of the graphs and use a calculator, done.
exp(5)(x-3) = -x + exp(3)
x - 3 + x = exp(3)/exp(5)
x = exp(-2)/2 + 3/2
Insert into either of the graphs and use a calculator, done.