A bike first accelerates from 0.0 m/s to 5.0 m/s in 4.5 s, then continues at this constant speed for another 4.5 s. What is the total distance traveled by the bike?
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a = (vf - vi) / t ===> a = 1.11 m/s^s (not needed... but good to know)
average velocity, Vavg:
Vavg = .5 (Vf - Vi) = 2.5 m/s
Displacement during acceleration, S:
S = Vavg * t = 2.5 * 4.5 = 11.25 meters
Displacement after acceleration, S:
S = 5 * 4.5 = 22.5 meter
Total S = 33.75 meters
This is about as easy as kinematics gets, so I'd suggest you study/try a bit harder if you plan on making the grade.
average velocity, Vavg:
Vavg = .5 (Vf - Vi) = 2.5 m/s
Displacement during acceleration, S:
S = Vavg * t = 2.5 * 4.5 = 11.25 meters
Displacement after acceleration, S:
S = 5 * 4.5 = 22.5 meter
Total S = 33.75 meters
This is about as easy as kinematics gets, so I'd suggest you study/try a bit harder if you plan on making the grade.
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Vavg = .5(Vf + Vi), but since Vi =0 it didn't change the outcome.
Sorry I missed that minus sign.
Sorry I missed that minus sign.
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