How man solutions are there to the equation: log_10 x = sin(2x*pi) ?
The answer is 19, but I don't know how to do it.
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Question 2:
Suppose three points are independently chosen at random on the perimeter of a circle. What is the probability that all three lie in some semicircle? [that is what is the probability that there is a linen passing thru the center of the circle such that all the points are on one side of that line]
the answer is 3/4, but I don't know how to get it.
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Thanks for your help!
The answer is 19, but I don't know how to do it.
______________________________________…
Question 2:
Suppose three points are independently chosen at random on the perimeter of a circle. What is the probability that all three lie in some semicircle? [that is what is the probability that there is a linen passing thru the center of the circle such that all the points are on one side of that line]
the answer is 3/4, but I don't know how to get it.
_______________-
Thanks for your help!
-
http://www.wolframalpha.com/input/?i=ln%…
they are numeric solutions
log x = sin(2πx)
x = 10^(sin2πx)
ln(x) = sin(2πx) ln(10)
ln(x) = ln(10) sin(2πx)
let left-hand side be:
y = ln(x)
let right-hand side be:
y = ln(10) sin(2πx)
the ln(10) is the amplitude and will determine the maximum value of y = ln(10) sin(2πx)
the two curves y = ln(10) sin(2πx) and y = ln(x) will have solutions where y = ln(x) is within the ln(10) amplitude
withing 0 ≤ x ≤ 10, there are 19 intersections.
ii)
n independent points
P(all n in some semicircle ) = n(½)^(n - 1)
n = 3 points
P(all 3 in some semicircle ) = 3(½)^(3 - 1) = ¾
they are numeric solutions
log x = sin(2πx)
x = 10^(sin2πx)
ln(x) = sin(2πx) ln(10)
ln(x) = ln(10) sin(2πx)
let left-hand side be:
y = ln(x)
let right-hand side be:
y = ln(10) sin(2πx)
the ln(10) is the amplitude and will determine the maximum value of y = ln(10) sin(2πx)
the two curves y = ln(10) sin(2πx) and y = ln(x) will have solutions where y = ln(x) is within the ln(10) amplitude
withing 0 ≤ x ≤ 10, there are 19 intersections.
ii)
n independent points
P(all n in some semicircle ) = n(½)^(n - 1)
n = 3 points
P(all 3 in some semicircle ) = 3(½)^(3 - 1) = ¾