Explain these math problem...

-first problem
the equation is 2x + (15x/100) = 1032 (where X is the original price of one toy)
when you solve this equation, you obtain that the price of each toy is X=480

-second problem
the equations are: X+(20X/100)=Y and X+(25X/100)=Y+89 (where X is the price of the bicycle and Y is the is the selling price of the bicycle)
when you solve this equation, you obtain that the price of the bicycle is X=1780

-third problem
this problem is unclear (to gain 50/3 what)

-fifth problem
the equation is (10X/100)=544 where X is the cost of the television
when you solve this equation , X=5440

-sixth problem (what does atv4 stand for)

-seventh problem
the equations are (5X/100)+X=Y and (35X/200)+X=Y+25
when you solve this system of equations, you find that the price of the article is X=200

ASK ONLY ONE QUESTION AT A TIME.
1) Let the cost price of each toy = Rs x
Selling price of the 1st toy = Rs (x + 5% of x) = Rs (x + x/20) = Rs 21x / 20
Selling price of the 2nd toy = Rs (x + 10% of x) = Rs (x + x/10) = Rs 11x / 10
Sum of the Selling prices of the 2 toys = Rs (21x / 20 + 11x / 10) = Rs 43x / 20
As per the question : 43x / 20 = 1032
=> x = 1032 * 20 / 43 = 480
Hence the cost price of each toy = Rs 480
Alternatively,
(105% + 110 %) of the Cost price of the toy = Rs1032
=> 215% of the Cost price of the toy = Rs1032
=> Cost price of the toy = Rs 1032 * 100 / 215 = Rs 480
2) (25% - 20%) of the Cost price of the bicycle = Rs 89
=> 5% of the Cost price of the bicycle = Rs 89
=> Cost price of the bicycle = Rs 89 * 100 / 5 = Rs 89 * 20 = Rs 1780
TRY THE REST OR ASK ONE AT A TIME

1) 1.05x + 1.10x = 1,032

2.15x = 1,032

x = 480

2) 1.2x + 89 = 1.25x

89 = 0.05x

x = 1,780

3) Not sure what you mean.

4) 1.2(0.85x - 0.085x) = 91.8%

5) 1.2x - 0.12x = 1.08x

0.08x = 544

x = 6,800

6) Not sure what you mean.

7) Not sure what you mean.