Explain these math problem...

the sum of the selling prices of 2
toys having the same cost price and
sold at profits of5% and 10% is
1032.then the cost price of each
toy is...

a bicycle was sold at a gain of 20%.
had it been sold for rs.89 more,the
gain would have been 25%.find the
cost price of the bicycle.

a vendor bought a 5 lemons for rs. 1. how many lemons can be bought for rs.7 to gain 50/3

a dealer buys goods. at 15% off the list price. he wants to make a profit of 20% after allowing. a discount of 10% . at what price above the list price. should he mark the goods?.

a trader marks a television. 20% above the cost price and allows a discount of 10% . if the profit earned is rs.544,then what is the cost price of the television?

a student. buys 3 pencils for rs.4 and sells all atv4 for rs.5. his gain or loss percent is..

a shopkeeper sold an article. at 5% profit . if he had sold it at a profit of 35/2.% the profit would. have. been. rs.25 more.what is the cost price of the article .

1) Let the cost price of each article be Rs X

1.05X + 1.1X = 1032

2.15X = 1032

X = 1032/2.15 = Rs 480 ANSWER

2) Let the cost of cycle be Rs 100x

20% profit = sold for Rs 120x

25% profit = Rs 120x + Rs 89

125x = 120x +89

5x = 89

100x = 89 X 20 = Rs 1780 ANSWER

3) Question is not clear

4) Let the list price be Rs 100x

15% off = Rs 85x = cost

20% profit = 1.2 X 85 = Rs 102x

Sale price after 10% discount is Rs 102x

So marked price = 100/90 X 102x = Rs 113.33x

Marked price - cost = Rs 13.33x over the list price ANSWER

5) Cost = Rs 100x

20% profit = Rs 120x

10% discount = Rs 12x

Sale price = Rs 108x

8x = Rs 544

100x = 100/8 X 544 = Rs 6800 ANSWER

6) Cost per pencil = Rs 4/3

Sale price per pencil =Rs 5/4

loss = 5/4 - 4/3 = 15/12 - 16 /12 = - 1/12